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Title: Mathematics question
Source: .
URL Source: http://.
Published: Mar 31, 2015
Author: .
Post Date: 2015-03-31 12:54:22 by Artisan
Keywords: None
Views: 701
Comments: 41

Can anyone tell me the formula I would use to solve this question.

If 2001.51 = 70% of X, what is X?

I know what X is, (2859.30) but if I didn't, and only had the 2001.51 number, what is the formula I would use to determine X?

And what area of math is this referred to as, (since I obviously need a course on it ;-) Thanks.

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#6. To: Artisan (#0)

That's a 6th grade math problem.

Abraham  posted on  2015-03-31   13:38:11 ET  Reply   Untrace   Trace   Private Reply  


#7. To: All (#6)

Thank you for pointing that out, Abraham. What would we do without you?

Are any of you seriously mathematical? If so I have a question that should be simple, but none of my local geniuses can answer it.

NeoconsNailed  posted on  2015-03-31   13:57:11 ET  Reply   Untrace   Trace   Private Reply  


#8. To: NeoconsNailed (#7)

If so I have a question that should be simple, but none of my local geniuses can answer it.

Shoot it here.

Fred Mertz  posted on  2015-03-31   14:00:07 ET  Reply   Untrace   Trace   Private Reply  


#13. To: Fred Mertz (#8)

Goody! How do you calculate the points at which the hour and minute hands of a clock are in the same exact position (or exactly opposite) other than 12:00?

Mind you, the exact times are of secondary interest at best. I mainly want to know how they'd be arrived at, simply because I'm an endlessly curious person (if a total mathematical failure).

NeoconsNailed  posted on  2015-03-31   15:03:57 ET  Reply   Untrace   Trace   Private Reply  


#26. To: NeoconsNailed (#13)

You can figure out the exact times the hands will be together and opposite, but it is a bit complicated:

Say starting at 12, you wanted to know the next time the hands would be together after 1. The hour hand moves 1/12 as fast as the minute hand. So the minute hand moves all the way around, but the hour hand moves only to one. When the minute hand gets to one the hour hand will be at 1 + 1/12.

Following this progression gives you the time when the two hands converge:

It is the infinite series 1 +1/12 +(1/12)^2 + 1/12^3.......

However this infinite series converges to definite value of 1 +1/(1 - 1/12). That is the next time the two hands will be together after 12. Using that point and the same method of calculation, you can follow the times around.

By simple geometry, it works the same way for when the hands are opposite. You could start with 12;30 and work your way around the clock.

Abraham  posted on  2015-03-31   17:49:41 ET  Reply   Untrace   Trace   Private Reply  


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