Iran Missiles Kinetically STRONER THAN ORESHNIK's /MIT Professor TED POSTOL

Source: https://www.youtube.com/watch?v=NEL5TRt9_PQ
Published: 2026-07-30
Author: Horse
Post Date: 2026-07-30 19:39:49 by Horse
Views: 142

 

Based on recent analyses by MIT Professor Theodore Postol regarding the ongoing conflict and Iran's missile capabilities (as of early 2026), here is the breakdown of the kinetic power and accuracy of Iran's advanced ballistic missiles, including those with MIRV (Multiple Independently-targetable Reentry Vehicle) capabilities:

Kinetic Power Postol highlights a significant evolution in Iran's warhead design, moving beyond simple explosive yield to leveraging kinetic energy as a primary destructive force.

High-Velocity Re-entry: Iran's newer ballistic missiles feature warheads that can maneuver at high altitudes and accelerate to speeds exceeding Mach 10 during re-entry.

(Mach 15 or 3.17 miles per second. At that speed, impact upon a solid target will compress the Kiloton weight of the warhead render a blast 2 to 2.5 times the explosive power of the warhead.)

 Powered Warheads: Some of these reentry vehicles are described as "powered," meaning they can accelerate upon re-entry rather than just decelerating due to atmospheric drag. This capability significantly reduces drag and doubles the explosive impact through kinetic energy 

 Impact on Defenses: This high kinetic energy makes the warheads harder to intercept and increases their ability to penetrate hardened targets, contributing to the "pain" Iran can inflict even against advanced air defenses .

Accuracy Postol argues that Iran's missile accuracy has improved dramatically, surpassing previous Western estimates and rendering many defense systems ineffective.

Precision Beyond 500 Meters: While earlier assessments estimated Iranian missile accuracy at around 500 meters, Postol notes that modern Iranian ballistic missiles are much more accurate than 500 meters, with evidence suggesting precision within tens of meters for certain systems 

 Real-Time Guidance: This high accuracy is facilitated by the use of commercially available high-tech components (such as infrared cameras and satellite navigation) and real-time guidance from control centers via satellite constellations like Iridium 

Satellite Intelligence: Iran leverages high-resolution, real-time satellite data provided by partners like China and Russia to update target coordinates, allowing for precise strikes on critical infrastructure .

MIRV Implications: While specific technical specs for MIRV dispersion are not detailed in the available transcripts, Postol emphasizes that the combination of high accuracy and maneuverable warheads allows Iran to effectively target multiple specific points within a city or base, overwhelming defenses with precise, high-kinetic strikes .

Strategic Context Postol emphasizes that the accuracy and kinetic power of these missiles are part of a broader strategy to overwhelm missile defense systems (like the Iron Dome, Patriot, and Arrow), which he describes as having very low interception rates (estimated at 1–2%) against such advanced threats

 . The ability to strike with high precision and kinetic force allows Iran to inflict significant damage despite the presence of sophisticated defense networks

 



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#1: Horse    To: Horse (#0)

 

 

Ted Postol, a physicist known for his work on missile defense and hypersonic weapons, typically relies on the standard classical kinetic energy formula when discussing the impact of projectiles like Mach 10+ missiles, unless he is addressing specific relativistic effects at extreme speeds.

The fundamental formula used is:

$$KE = \frac{1}{2}mv^2$$

Where:

$KE$ is the Kinetic Energy (usually in Joules).

$m$ is the mass of the missile (in kilograms).

$v$ is the velocity of the missile (in meters per second).

For a Mach 10+ missile, the velocity ($v$) is approximately 10 times the speed of sound. At sea level, the speed of sound is roughly 343 m/s, meaning Mach 10 is about 3,430 m/s (though this increases slightly at higher altitudes due to temperature changes).

Key Considerations in Postol's Analysis:

Velocity Squared: Because velocity is squared in the equation, small increases in speed result in massive increases in energy. A missile traveling at Mach 10 carries roughly 100 times more kinetic energy than the same missile traveling at Mach 1.

Relativistic Effects: At Mach 10 (approx. 3.4 km/s), the object is moving at roughly 0.001% the speed of light. Standard classical physics ($\frac{1}{2}mv^2$) is sufficiently accurate here; relativistic corrections are negligible and generally not part of the standard calculation unless speeds approach a significant fraction of the speed of light.

Atmospheric Interaction: Postol often emphasizes that the effective energy delivered to the ground can be reduced by atmospheric drag, ablation, or breakup during re-entry, though the theoretical kinetic energy is calculated using the mass and velocity at the moment of impact.

  

 

To calculate the kinetic energy of a 1-kiloton warhead (referring to its mass, not its explosive yield) hitting the ground at Mach 15, we must first clarify the mass and then apply the standard kinetic energy formula.

Important Distinction: In military terminology, a "1 kiloton warhead" usually refers to the explosive yield (energy released by the explosion), not the physical mass of the object.

If you mean a warhead with a 1 kiloton explosive yield, the mass could be anywhere from a few hundred kilograms to a few tons depending on the efficiency of the explosive material.

If you mean a warhead with a physical mass of 1 kiloton (1,000,000 kg), that is an enormous object (equivalent to the mass of about 160 adult blue whales or a large ocean liner), which is highly unlikely for a missile warhead.

I will provide the calculation for both scenarios so you can see the difference.

Scenario A: The Warhead has a physical mass of 1,000 kg (1 Metric Ton)This is a more realistic mass for a heavy warhead, though still large.

Mass ($m$): $1,000 \text{ kg}$

Velocity ($v$): Mach 15.Speed of sound at sea level $\approx 343 \text{ m/s}$.

$v = 15 \times 343 = 5,145 \text{ m/s}$.

 

Formula: $KE = \frac{1}{2}mv^2$

Calculation: $$KE = 0.5 \times 1,000 \times (5,145)^2$$ $$KE = 500 \times 26,471,025$$ $$KE \approx 13,235,512,500 \text{ Joules}$$

Result: Approximately 13.2 Gigajoules (GJ).

To put this in perspective:

1 ton of TNT $\approx 4.184 \text{ Gigajoules}$.

$13.2 \text{ GJ} / 4.184 \text{ GJ} \approx$ 3.15 tons of TNT equivalent in kinetic energy alone.

Scenario B: The Warhead has a physical mass of 1,000,000 kg (1 Kiloton mass)This is the literal interpretation of "1 kiloton warhead" as a mass unit, though physically unrealistic for a missile.

Mass ($m$): $1,000,000 \text{ kg}$

Velocity ($v$): $5,145 \text{ m/s}$

Calculation: $$KE = 0.5 \times 1,000,000 \times (5,145)^2$$ $$KE = 500,000 \times 26,471,025$$ $$KE \approx 13,235,512,500,000 \text{ Joules}$$

Result: Approximately 13,235 Gigajoules (or 13.2 Terajoules).

In TNT equivalent: $\approx$ 3,150 tons of TNT (3.15 kilotons).

Comparison to Explosive YieldIf the "1 kiloton" in your question referred to the explosive yield (chemical/nuclear energy) rather than mass:

A standard 1-kiloton nuclear warhead releases 4.184 Terajoules of energy upon detonation.

If that same warhead (mass $\approx 300\text{--}500 \text{ kg}$) hits the ground at Mach 15, its kinetic energy might be roughly 2 to 4 GJ (0.5 to 1 kiloton equivalent).

In this case, the kinetic energy is comparable to the explosive yield, effectively doubling the destructive power if the kinetic energy is fully transferred to the ground (like a bunker buster) or causing massive cratering even if the warhead doesn't detonate.

Summary: The kinetic energy depends entirely on the mass.

For a 1-ton mass at Mach 15: ~13.2 GJ (approx. 3 tons of TNT).

For a 1,000-ton mass at Mach 15: ~13,200 GJ (approx. 3,150 tons of TNT).

Most real-world hypersonic missiles (like the Kinzhal or Zircon) have warhead masses in the range of 300 kg to 1,000 kg. At Mach 10–15, their kinetic energy alone often rivals or exceeds the yield of their conventional high-explosive warheads.

 

Horse posted on 2026-07-30 19:46:12   Reply   Private Reply


#2: Horse    To: Horse (#1)

 

 

Thank you for the clarification.

If the mass is 1,000 kilograms (1 metric ton) and the velocity is Mach 15, here is the precise calculation for the kinetic energy.

The Calculation1. Define the variables:

Mass ($m$): $1,000 \text{ kg}$

Velocity ($v$): Mach 15.The speed of sound ($c$) varies with altitude and temperature.

At sea level (standard conditions): $c \approx 343 \text{ m/s}$.

At high altitude (stratosphere, ~11–20 km): $c \approx 295 \text{ m/s}$ (colder air).

Assumption: We will use the standard sea-level speed ($343 \text{ m/s}$) as a baseline, but note that a missile striking the ground from a high altitude trajectory might have a slightly different Mach conversion depending on the atmospheric model used.

$v = 15 \times 343 = 5,145 \text{ m/s}$.

 

2. Apply the Kinetic Energy formula: $$KE = \frac{1}{2}mv^2$$

3. Execute the math: $$KE = 0.5 \times 1,000 \text{ kg} \times (5,145 \text{ m/s})^2$$ $$KE = 500 \times 26,471,025$$ $$KE = 13,235,512,500 \text{ Joules}$$

The ResultThe kinetic energy released would be approximately 13.24 Gigajoules (GJ).

Context: Comparison to ExplosivesTo understand the destructive power of this impact without an explosive warhead, we convert this energy into TNT equivalent.

1 ton of TNT $\approx 4.184 \text{ Gigajoules}$.

$13.24 \text{ GJ} / 4.184 \text{ GJ/ton} \approx$ 3.16 tons of TNT.

Summary of Impact: A 1,000 kg (1 ton) object hitting the ground at Mach 15 releases kinetic energy equivalent to detonating roughly 3.2 tons of TNT.

Comparison to the warhead yield you mentioned earlier: If this were a "1 kiloton" (1,000 tons of TNT) nuclear warhead, the kinetic energy (3.2 tons of TNT) would be a tiny fraction (0.3%) of the nuclear yield.

Comparison to conventional warheads: If this were a conventional high-explosive warhead, a typical large missile warhead might contain 200–500 kg of explosives (yielding roughly 0.5–1 ton of TNT). In this specific scenario, the kinetic energy alone (3.2 tons TNT) is 3 to 6 times more powerful than the chemical explosion of a standard large conventional warhead.

This illustrates why hypersonic kinetic impactors (missiles designed to destroy targets purely by speed and mass) are so destructive: the velocity term is squared, making speed the dominant factor in the energy equation.

 

 

 

Horse posted on 2026-07-30 19:50:25   Reply   Private Reply